Base | Representation |
---|---|
bin | 110011001110111010… |
… | …1000000101111111101 |
3 | 101111222121222212122011 |
4 | 1212131311000233331 |
5 | 3300311124231023 |
6 | 122313215251221 |
7 | 10643310302545 |
oct | 1463565005775 |
9 | 344877885564 |
10 | 110022102013 |
11 | 4272967673a |
12 | 193a6219b11 |
13 | a4b4c68015 |
14 | 547a0d8325 |
15 | 2cde01150d |
hex | 199dd40bfd |
110022102013 has 4 divisors (see below), whose sum is σ = 110032090560. Its totient is φ = 110012113468.
The previous prime is 110022102011. The next prime is 110022102017. The reversal of 110022102013 is 310201220011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 110022102013 - 21 = 110022102011 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110022101984 and 110022102002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110022102011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4977733 + ... + 4999786.
It is an arithmetic number, because the mean of its divisors is an integer number (27508022640).
Almost surely, 2110022102013 is an apocalyptic number.
It is an amenable number.
110022102013 is a deficient number, since it is larger than the sum of its proper divisors (9988547).
110022102013 is an equidigital number, since it uses as much as digits as its factorization.
110022102013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9988546.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 110022102013 its reverse (310201220011), we get a palindrome (420223322024).
The spelling of 110022102013 in words is "one hundred ten billion, twenty-two million, one hundred two thousand, thirteen".
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