Base | Representation |
---|---|
bin | 1010000000011010011011… |
… | …1000010010100011010011 |
3 | 1102221210122000002002010122 |
4 | 2200012212320102203103 |
5 | 2420230012010101323 |
6 | 35222202421220455 |
7 | 2213612021424623 |
oct | 240064670224323 |
9 | 42853560062118 |
10 | 11002211018963 |
11 | 356201432520a |
12 | 129837626172b |
13 | 61a672512cb8 |
14 | 2a071d080883 |
15 | 1412d5850ec8 |
hex | a01a6e128d3 |
11002211018963 has 2 divisors, whose sum is σ = 11002211018964. Its totient is φ = 11002211018962.
The previous prime is 11002211018951. The next prime is 11002211018971. The reversal of 11002211018963 is 36981011220011.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (36981011220011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11002211018963 - 210 = 11002211017939 is a prime.
It is not a weakly prime, because it can be changed into another prime (11002211018983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501105509481 + 5501105509482.
It is an arithmetic number, because the mean of its divisors is an integer number (5501105509482).
Almost surely, 211002211018963 is an apocalyptic number.
11002211018963 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002211018963 is an equidigital number, since it uses as much as digits as its factorization.
11002211018963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 35.
Adding to 11002211018963 its reverse (36981011220011), we get a palindrome (47983222238974).
The spelling of 11002211018963 in words is "eleven trillion, two billion, two hundred eleven million, eighteen thousand, nine hundred sixty-three".
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