Base | Representation |
---|---|
bin | 1010000000011010011101… |
… | …1110110100100111001111 |
3 | 1102221210122201002021002022 |
4 | 2200012213132310213033 |
5 | 2420230022101314301 |
6 | 35222203421520355 |
7 | 2213612203324565 |
oct | 240064736644717 |
9 | 42853581067068 |
10 | 11002221119951 |
11 | 3562019aa4236 |
12 | 12983797130bb |
13 | 61a67463b809 |
14 | 2a072054da35 |
15 | 1412d6698d1b |
hex | a01a77b49cf |
11002221119951 has 2 divisors, whose sum is σ = 11002221119952. Its totient is φ = 11002221119950.
The previous prime is 11002221119947. The next prime is 11002221119983. The reversal of 11002221119951 is 15991112220011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11002221119951 - 22 = 11002221119947 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11002221119921) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501110559975 + 5501110559976.
It is an arithmetic number, because the mean of its divisors is an integer number (5501110559976).
Almost surely, 211002221119951 is an apocalyptic number.
11002221119951 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002221119951 is an equidigital number, since it uses as much as digits as its factorization.
11002221119951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 35.
Adding to 11002221119951 its reverse (15991112220011), we get a palindrome (26993333339962).
The spelling of 11002221119951 in words is "eleven trillion, two billion, two hundred twenty-one million, one hundred nineteen thousand, nine hundred fifty-one".
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