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110022312013 is a prime number
BaseRepresentation
bin110011001110111010…
…1110100000001001101
3101111222122101112200221
41212131311310001031
53300311202441023
6122313223551341
710643312136025
oct1463565640115
9344878345627
10110022312013
11427297aa499
12193a62bb551
13a4b500c793
14547a150a85
152cde05385d
hex199dd7404d

110022312013 has 2 divisors, whose sum is σ = 110022312014. Its totient is φ = 110022312012.

The previous prime is 110022311989. The next prime is 110022312031. The reversal of 110022312013 is 310213220011.

Together with next prime (110022312031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69927455844 + 40094856169 = 264438^2 + 200237^2 .

It is an emirp because it is prime and its reverse (310213220011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110022312013 is a prime.

It is a super-2 number, since 2×1100223120132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110022312083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011156006 + 55011156007.

It is an arithmetic number, because the mean of its divisors is an integer number (55011156007).

Almost surely, 2110022312013 is an apocalyptic number.

It is an amenable number.

110022312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

110022312013 is an equidigital number, since it uses as much as digits as its factorization.

110022312013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 110022312013 its reverse (310213220011), we get a palindrome (420235532024).

The spelling of 110022312013 in words is "one hundred ten billion, twenty-two million, three hundred twelve thousand, thirteen".