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1100230433 is a prime number
BaseRepresentation
bin100000110010100…
…0010111100100001
32211200021111102022
41001211002330201
54223124333213
6301101431225
736156542621
oct10145027441
92750244368
101100230433
11515062455
1226856b515
13146c31833
14a619c881
15668ce308
hex41942f21

1100230433 has 2 divisors, whose sum is σ = 1100230434. Its totient is φ = 1100230432.

The previous prime is 1100230399. The next prime is 1100230451. The reversal of 1100230433 is 3340320011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 735114769 + 365115664 = 27113^2 + 19108^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100230433 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100230133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550115216 + 550115217.

It is an arithmetic number, because the mean of its divisors is an integer number (550115217).

Almost surely, 21100230433 is an apocalyptic number.

It is an amenable number.

1100230433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100230433 is an equidigital number, since it uses as much as digits as its factorization.

1100230433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 17.

The square root of 1100230433 is about 33169.7216298238. The cubic root of 1100230433 is about 1032.3521926672.

Adding to 1100230433 its reverse (3340320011), we get a palindrome (4440550444).

The spelling of 1100230433 in words is "one billion, one hundred million, two hundred thirty thousand, four hundred thirty-three".