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110023430441 is a prime number
BaseRepresentation
bin110011001110111101…
…0000101000100101001
3101111222201111100220012
41212131322011010221
53300311444233231
6122313303541305
710643324504531
oct1463572050451
9344881440805
10110023430441
114272a3a3811
12193a675a835
13a4b5311882
14547a3624c1
152cde1c4e2b
hex199de85129

110023430441 has 2 divisors, whose sum is σ = 110023430442. Its totient is φ = 110023430440.

The previous prime is 110023430383. The next prime is 110023430443. The reversal of 110023430441 is 144034320011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78064360000 + 31959070441 = 279400^2 + 178771^2 .

It is an emirp because it is prime and its reverse (144034320011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110023430441 - 222 = 110019236137 is a prime.

Together with 110023430443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (110023430443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011715220 + 55011715221.

It is an arithmetic number, because the mean of its divisors is an integer number (55011715221).

Almost surely, 2110023430441 is an apocalyptic number.

It is an amenable number.

110023430441 is a deficient number, since it is larger than the sum of its proper divisors (1).

110023430441 is an equidigital number, since it uses as much as digits as its factorization.

110023430441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 110023430441 its reverse (144034320011), we get a palindrome (254057750452).

It can be divided in two parts, 11002 and 3430441, that added together give a palindrome (3441443).

The spelling of 110023430441 in words is "one hundred ten billion, twenty-three million, four hundred thirty thousand, four hundred forty-one".