11002345031131 has 2 divisors, whose sum is σ = 11002345031132. Its totient is φ = 11002345031130.

The previous prime is 11002345031123. The next prime is 11002345031141. The reversal of 11002345031131 is 13113054320011.

11002345031131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11002345031131 - 2³ = 11002345031123 is a prime.

It is a super-2 number, since 2×11002345031131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11002345031096 and 11002345031105.

It is not a weakly prime, because it can be changed into another prime (11002345031141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501172515565 + 5501172515566.

It is an arithmetic number, because the mean of its divisors is an integer number (5501172515566).

Almost surely, 2^{11002345031131} is an apocalyptic number.

11002345031131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002345031131 is an equidigital number, since it uses as much as digits as its factorization.

11002345031131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 11002345031131 its reverse (13113054320011), we get a palindrome (24115399351142).

The spelling of 11002345031131 in words is "eleven trillion, two billion, three hundred forty-five million, thirty-one thousand, one hundred thirty-one".