Base | Representation |
---|---|
bin | 10100011111101010… |
… | …10001110111100110 |
3 | 1001101211011111212022 |
4 | 22033311101313212 |
5 | 140013234341202 |
6 | 5015453223142 |
7 | 536444216306 |
oct | 121765216746 |
9 | 31354144768 |
10 | 11003043302 |
11 | 4736a27319 |
12 | 2170a91ab2 |
13 | 1064751914 |
14 | 765463606 |
15 | 445e90ea2 |
hex | 28fd51de6 |
11003043302 has 4 divisors (see below), whose sum is σ = 16504564956. Its totient is φ = 5501521650.
The previous prime is 11003043283. The next prime is 11003043341. The reversal of 11003043302 is 20334030011.
It is a happy number.
11003043302 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20334030011 = 1553 ⋅13093387.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750760824 + ... + 2750760827.
It is an arithmetic number, because the mean of its divisors is an integer number (4126141239).
Almost surely, 211003043302 is an apocalyptic number.
11003043302 is a deficient number, since it is larger than the sum of its proper divisors (5501521654).
11003043302 is an equidigital number, since it uses as much as digits as its factorization.
11003043302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5501521653.
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 11003043302 its reverse (20334030011), we get a palindrome (31337073313).
The spelling of 11003043302 in words is "eleven billion, three million, forty-three thousand, three hundred two".
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