110031113 has 2 divisors, whose sum is σ = 110031114. Its totient is φ = 110031112.

The previous prime is 110031107. The next prime is 110031143. The reversal of 110031113 is 311130011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104796169 + 5234944 = 10237^2 + 2288^2 .

It is an emirp because it is prime and its reverse (311130011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110031113 - 2⁸ = 110030857 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 110031094 and 110031103.

It is not a weakly prime, because it can be changed into another prime (110031143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55015556 + 55015557.

It is an arithmetic number, because the mean of its divisors is an integer number (55015557).

Almost surely, 2^110031113 is an apocalyptic number.

It is an amenable number.

110031113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110031113 is an equidigital number, since it uses as much as digits as its factorization.

110031113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 11.

The square root of 110031113 is about 10489.5716309104. The cubic root of 110031113 is about 479.1871558254.

Adding to 110031113 its reverse (311130011), we get a palindrome (421161124).

The spelling of 110031113 in words is "one hundred ten million, thirty-one thousand, one hundred thirteen".