Base | Representation |
---|---|
bin | 1010000000011101110010… |
… | …0101101101111111110111 |
3 | 1102221212221210122202210122 |
4 | 2200013130211231333313 |
5 | 2420233333200322221 |
6 | 35222432051042155 |
7 | 2213643242601353 |
oct | 240073445557767 |
9 | 42855853582718 |
10 | 11003112120311 |
11 | 3562436a39a73 |
12 | 1298587ba035b |
13 | 61a787103a6c |
14 | 2a07a6a06463 |
15 | 1413399e8eab |
hex | a01dc96dff7 |
11003112120311 has 2 divisors, whose sum is σ = 11003112120312. Its totient is φ = 11003112120310.
The previous prime is 11003112120223. The next prime is 11003112120317. The reversal of 11003112120311 is 11302121130011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11003112120311 is a prime.
It is a super-3 number, since 3×110031121203113 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11003112120311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11003112120317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501556060155 + 5501556060156.
It is an arithmetic number, because the mean of its divisors is an integer number (5501556060156).
Almost surely, 211003112120311 is an apocalyptic number.
11003112120311 is a deficient number, since it is larger than the sum of its proper divisors (1).
11003112120311 is an equidigital number, since it uses as much as digits as its factorization.
11003112120311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 11003112120311 its reverse (11302121130011), we get a palindrome (22305233250322).
The spelling of 11003112120311 in words is "eleven trillion, three billion, one hundred twelve million, one hundred twenty thousand, three hundred eleven".
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