110031213123108 has 36 divisors (see below), whose sum is σ = 278251269746268. Its totient is φ = 36661666950720.

The previous prime is 110031213123077. The next prime is 110031213123109. The reversal of 110031213123108 is 801321312130011.

110031213123108 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 31 + 2 + 1 + 312 + 310 + 8 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 13119159273444 + 96912053849664 = 3622038^2 + 9844392^2 .

It is a tau number, because it is divible by the number of its divisors (36).

It is a super-2 number, since 2×110031213123108² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (110031213123109) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 641750191 + ... + 641921622.

Almost surely, 2^{110031213123108} is an apocalyptic number.

110031213123108 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

It is an amenable number.

110031213123108 is an abundant number, since it is smaller than the sum of its proper divisors (168220056623160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110031213123108 is a wasteful number, since it uses less digits than its factorization.

110031213123108 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1283674204 (or 1283674199 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 27.

Adding to 110031213123108 its reverse (801321312130011), we get a palindrome (911352525253119).

The spelling of 110031213123108 in words is "one hundred ten trillion, thirty-one billion, two hundred thirteen million, one hundred twenty-three thousand, one hundred eight".