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110031213123109 is a prime number
BaseRepresentation
bin11001000001001010100011…
…010111110101011000100101
3112102120212210102112201112201
4121001022203113311120211
5103410222411024414414
61030003350321214501
732114331014631505
oct3101124327653045
9472525712481481
10110031213123109
1132071a80333603
1210410952791431
134951b8baa3c85
141d25779533a05
15cac26eaba574
hex6412a35f5625

110031213123109 has 2 divisors, whose sum is σ = 110031213123110. Its totient is φ = 110031213123108.

The previous prime is 110031213123077. The next prime is 110031213123127. The reversal of 110031213123109 is 901321312130011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74561446200609 + 35469766922500 = 8634897^2 + 5955650^2 .

It is a cyclic number.

It is not a de Polignac number, because 110031213123109 - 25 = 110031213123077 is a prime.

It is a super-2 number, since 2×1100312131231092 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110031213123179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55015606561554 + 55015606561555.

It is an arithmetic number, because the mean of its divisors is an integer number (55015606561555).

Almost surely, 2110031213123109 is an apocalyptic number.

It is an amenable number.

110031213123109 is a deficient number, since it is larger than the sum of its proper divisors (1).

110031213123109 is an equidigital number, since it uses as much as digits as its factorization.

110031213123109 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 28.

The spelling of 110031213123109 in words is "one hundred ten trillion, thirty-one billion, two hundred thirteen million, one hundred twenty-three thousand, one hundred nine".