1100321317 has 2 divisors, whose sum is σ = 1100321318. Its totient is φ = 1100321316.

The previous prime is 1100321309. The next prime is 1100321333. The reversal of 1100321317 is 7131230011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1097331876 + 2989441 = 33126^2 + 1729^2 .

It is an emirp because it is prime and its reverse (7131230011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100321317 - 2³ = 1100321309 is a prime.

It is a super-2 number, since 2×1100321317² = 2421414001289228978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100321294 and 1100321303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100331317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550160658 + 550160659.

It is an arithmetic number, because the mean of its divisors is an integer number (550160659).

Almost surely, 2^1100321317 is an apocalyptic number.

It is an amenable number.

1100321317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100321317 is an equidigital number, since it uses as much as digits as its factorization.

1100321317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 19.

The square root of 1100321317 is about 33171.0915858975. The cubic root of 1100321317 is about 1032.3806175348.

Adding to 1100321317 its reverse (7131230011), we get a palindrome (8231551328).

The spelling of 1100321317 in words is "one billion, one hundred million, three hundred twenty-one thousand, three hundred seventeen".