Base | Representation |
---|---|
bin | 10000000000110000010… |
… | …011011001111010110001 |
3 | 10220012010100000010112222 |
4 | 100000300103121322301 |
5 | 121011424414133131 |
6 | 2201251515330425 |
7 | 142332001601255 |
oct | 20006023317261 |
9 | 3805110003488 |
10 | 1100322021041 |
11 | 39470a106191 |
12 | 1592bb750a15 |
13 | 7c9b5716379 |
14 | 3b382170265 |
15 | 1d94ddae87b |
hex | 100304d9eb1 |
1100322021041 has 2 divisors, whose sum is σ = 1100322021042. Its totient is φ = 1100322021040.
The previous prime is 1100322021017. The next prime is 1100322021049. The reversal of 1100322021041 is 1401202230011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 564601960000 + 535720061041 = 751400^2 + 731929^2 .
It is an emirp because it is prime and its reverse (1401202230011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1100322021041 - 222 = 1100317826737 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1100322021049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550161010520 + 550161010521.
It is an arithmetic number, because the mean of its divisors is an integer number (550161010521).
Almost surely, 21100322021041 is an apocalyptic number.
It is an amenable number.
1100322021041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100322021041 is an equidigital number, since it uses as much as digits as its factorization.
1100322021041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1100322021041 its reverse (1401202230011), we get a palindrome (2501524251052).
The spelling of 1100322021041 in words is "one trillion, one hundred billion, three hundred twenty-two million, twenty-one thousand, forty-one".
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