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110033242329949 is a prime number
BaseRepresentation
bin11001000001001100011100…
…010100101001001101011101
3112102121002000211212010000121
4121001030130110221031131
5103410241040014024244
61030004323530154541
732114432214616441
oct3101143424511535
9472532024763017
10110033242329949
1132072921809754
121041121a282a51
134952123306293
141d258ccc32821
15cac33ccebc84
hex64131c52935d

110033242329949 has 2 divisors, whose sum is σ = 110033242329950. Its totient is φ = 110033242329948.

The previous prime is 110033242329931. The next prime is 110033242330043. The reversal of 110033242329949 is 949923242330011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70109105041924 + 39924137288025 = 8373118^2 + 6318555^2 .

It is a cyclic number.

It is not a de Polignac number, because 110033242329949 - 243 = 101237149307741 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110033242329896 and 110033242329905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110033242329919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55016621164974 + 55016621164975.

It is an arithmetic number, because the mean of its divisors is an integer number (55016621164975).

Almost surely, 2110033242329949 is an apocalyptic number.

It is an amenable number.

110033242329949 is a deficient number, since it is larger than the sum of its proper divisors (1).

110033242329949 is an equidigital number, since it uses as much as digits as its factorization.

110033242329949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2519424, while the sum is 52.

The spelling of 110033242329949 in words is "one hundred ten trillion, thirty-three billion, two hundred forty-two million, three hundred twenty-nine thousand, nine hundred forty-nine".