1100333120113 has 2 divisors, whose sum is σ = 1100333120114. Its totient is φ = 1100333120112.

The previous prime is 1100333120023. The next prime is 1100333120141. The reversal of 1100333120113 is 3110213330011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 970122562704 + 130210557409 = 984948^2 + 360847^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100333120113 - 2¹³ = 1100333111921 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100333120213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550166560056 + 550166560057.

It is an arithmetic number, because the mean of its divisors is an integer number (550166560057).

Almost surely, 2^{1100333120113} is an apocalyptic number.

It is an amenable number.

1100333120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100333120113 is an equidigital number, since it uses as much as digits as its factorization.

1100333120113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1100333120113 its reverse (3110213330011), we get a palindrome (4210546450124).

The spelling of 1100333120113 in words is "one trillion, one hundred billion, three hundred thirty-three million, one hundred twenty thousand, one hundred thirteen".