Base | Representation |
---|---|
bin | 10000000000110000111… |
… | …101101111101010001101 |
3 | 10220012011002220000122202 |
4 | 100000300331233222031 |
5 | 121011440234321031 |
6 | 2201252553251245 |
7 | 142332165126203 |
oct | 20006075575215 |
9 | 3805132800582 |
10 | 1100333120141 |
11 | 3947153a70a2 |
12 | 159303403b25 |
13 | 7c9b7b01298 |
14 | 3b38381d073 |
15 | 1d94ed532cb |
hex | 10030f6fa8d |
1100333120141 has 2 divisors, whose sum is σ = 1100333120142. Its totient is φ = 1100333120140.
The previous prime is 1100333120113. The next prime is 1100333120209. The reversal of 1100333120141 is 1410213330011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1098190818916 + 2142301225 = 1047946^2 + 46285^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100333120141 - 226 = 1100266011277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100333120941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550166560070 + 550166560071.
It is an arithmetic number, because the mean of its divisors is an integer number (550166560071).
Almost surely, 21100333120141 is an apocalyptic number.
It is an amenable number.
1100333120141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100333120141 is an equidigital number, since it uses as much as digits as its factorization.
1100333120141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1100333120141 its reverse (1410213330011), we get a palindrome (2510546450152).
The spelling of 1100333120141 in words is "one trillion, one hundred billion, three hundred thirty-three million, one hundred twenty thousand, one hundred forty-one".
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