Base | Representation |
---|---|
bin | 1010000000011110100111… |
… | …1100010111101111000010 |
3 | 1102221220112102020021112221 |
4 | 2200013221330113233002 |
5 | 2420234313024142432 |
6 | 35222510213041254 |
7 | 2213651633121004 |
oct | 240075174275702 |
9 | 42856472207487 |
10 | 11003336162242 |
11 | 3562541452a96 |
12 | 129862b02622a |
13 | 61a7c1658158 |
14 | 2a07c8686374 |
15 | 14134e501b97 |
hex | a01e9f17bc2 |
11003336162242 has 4 divisors (see below), whose sum is σ = 16505004243366. Its totient is φ = 5501668081120.
The previous prime is 11003336162213. The next prime is 11003336162263. The reversal of 11003336162242 is 24226163330011.
It is a happy number.
11003336162242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11001951652561 + 1384509681 = 3316919^2 + 37209^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11003336162198 and 11003336162207.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750834040559 + ... + 2750834040562.
Almost surely, 211003336162242 is an apocalyptic number.
11003336162242 is a deficient number, since it is larger than the sum of its proper divisors (5501668081124).
11003336162242 is an equidigital number, since it uses as much as digits as its factorization.
11003336162242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5501668081123.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 11003336162242 its reverse (24226163330011), we get a palindrome (35229499492253).
The spelling of 11003336162242 in words is "eleven trillion, three billion, three hundred thirty-six million, one hundred sixty-two thousand, two hundred forty-two".
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