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110034101 is a prime number
BaseRepresentation
bin1101000111011…
…11110010110101
321200001022102002
412203233302311
5211132042401
614530225045
72504163062
oct643576265
9250038362
10110034101
1157125281
1230a25185
1319a47a48
1410883c69
1599d7a6b
hex68efcb5

110034101 has 2 divisors, whose sum is σ = 110034102. Its totient is φ = 110034100.

The previous prime is 110034077. The next prime is 110034107. The reversal of 110034101 is 101430011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80982001 + 29052100 = 8999^2 + 5390^2 .

It is an emirp because it is prime and its reverse (101430011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110034101 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110034107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55017050 + 55017051.

It is an arithmetic number, because the mean of its divisors is an integer number (55017051).

Almost surely, 2110034101 is an apocalyptic number.

It is an amenable number.

110034101 is a deficient number, since it is larger than the sum of its proper divisors (1).

110034101 is an equidigital number, since it uses as much as digits as its factorization.

110034101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 110034101 is about 10489.7140571133. The cubic root of 110034101 is about 479.1914933812.

Adding to 110034101 its reverse (101430011), we get a palindrome (211464112).

The spelling of 110034101 in words is "one hundred ten million, thirty-four thousand, one hundred one".