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11003413441020 = 2235721113373372099
BaseRepresentation
bin1010000000011110111010…
…0011001010100111111100
31102221220201210122110002220
42200013232203022213330
52420234442320103040
635222522013245340
72213653562021400
oct240075643124774
942856653573086
1011003413441020
113562581035750
121298650a93850
1361a804674a40
142a07d4a41100
151413561b92d0
hexa01ee8ca9fc

11003413441020 has 1152 divisors, whose sum is σ = 43392334003200. Its totient is φ = 2046434181120.

The previous prime is 11003413441019. The next prime is 11003413441021. The reversal of 11003413441020 is 2014431430011.

11003413441020 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11003413441019) and next prime (11003413441021).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11003413441021) by changing a digit.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 5242215931 + ... + 5242218029.

It is an arithmetic number, because the mean of its divisors is an integer number (37666956600).

Almost surely, 211003413441020 is an apocalyptic number.

11003413441020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11003413441020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21696167001600).

11003413441020 is an abundant number, since it is smaller than the sum of its proper divisors (32388920562180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11003413441020 is a wasteful number, since it uses less digits than its factorization.

11003413441020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2523 (or 2514 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 11003413441020 its reverse (2014431430011), we get a palindrome (13017844871031).

The spelling of 11003413441020 in words is "eleven trillion, three billion, four hundred thirteen million, four hundred forty-one thousand, twenty".