110035301420041 has 2 divisors, whose sum is σ = 110035301420042. Its totient is φ = 110035301420040.

The previous prime is 110035301419957. The next prime is 110035301420071. The reversal of 110035301420041 is 140024103530011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100427756463225 + 9607544956816 = 10021365^2 + 3099604^2 .

It is a cyclic number.

It is not a de Polignac number, because 110035301420041 - 2⁷ = 110035301419913 is a prime.

It is a super-2 number, since 2×110035301420041² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110035301419988 and 110035301420015.

It is not a weakly prime, because it can be changed into another prime (110035301420071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55017650710020 + 55017650710021.

It is an arithmetic number, because the mean of its divisors is an integer number (55017650710021).

Almost surely, 2^{110035301420041} is an apocalyptic number.

It is an amenable number.

110035301420041 is a deficient number, since it is larger than the sum of its proper divisors (1).

110035301420041 is an equidigital number, since it uses as much as digits as its factorization.

110035301420041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 110035301420041 its reverse (140024103530011), we get a palindrome (250059404950052).

The spelling of 110035301420041 in words is "one hundred ten trillion, thirty-five billion, three hundred one million, four hundred twenty thousand, forty-one".