1100401430081 has 2 divisors, whose sum is σ = 1100401430082. Its totient is φ = 1100401430080.

The previous prime is 1100401430069. The next prime is 1100401430171. The reversal of 1100401430081 is 1800341040011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 797993823025 + 302407607056 = 893305^2 + 549916^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100401430081 is a prime.

It is a super-2 number, since 2×1100401430081² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100401330081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550200715040 + 550200715041.

It is an arithmetic number, because the mean of its divisors is an integer number (550200715041).

Almost surely, 2^{1100401430081} is an apocalyptic number.

It is an amenable number.

1100401430081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100401430081 is an equidigital number, since it uses as much as digits as its factorization.

1100401430081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1100401430081 its reverse (1800341040011), we get a palindrome (2900742470092).

The spelling of 1100401430081 in words is "one trillion, one hundred billion, four hundred one million, four hundred thirty thousand, eighty-one".