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11004052502533 is a prime number
BaseRepresentation
bin1010000000100001010010…
…1000111111100000000101
31102221222101100011010200211
42200020110220333200011
52420242244420040113
635223105242435421
72214005451656446
oct240102450774005
942858340133624
1011004052502533
113562879843062
1212987aab02b71
1361a8a6b98c4c
142a08558752cd
15141392350b3d
hexa0214a3f805

11004052502533 has 2 divisors, whose sum is σ = 11004052502534. Its totient is φ = 11004052502532.

The previous prime is 11004052502501. The next prime is 11004052502539. The reversal of 11004052502533 is 33520525040011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7935049554084 + 3069002948449 = 2816922^2 + 1751857^2 .

It is a cyclic number.

It is not a de Polignac number, because 11004052502533 - 25 = 11004052502501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11004052502495 and 11004052502504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11004052502539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502026251266 + 5502026251267.

It is an arithmetic number, because the mean of its divisors is an integer number (5502026251267).

Almost surely, 211004052502533 is an apocalyptic number.

It is an amenable number.

11004052502533 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004052502533 is an equidigital number, since it uses as much as digits as its factorization.

11004052502533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 11004052502533 its reverse (33520525040011), we get a palindrome (44524577542544).

The spelling of 11004052502533 in words is "eleven trillion, four billion, fifty-two million, five hundred two thousand, five hundred thirty-three".