1100411132321 has 2 divisors, whose sum is σ = 1100411132322. Its totient is φ = 1100411132320.

The previous prime is 1100411132297. The next prime is 1100411132323. The reversal of 1100411132321 is 1232311140011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1098607941025 + 1803191296 = 1048145^2 + 42464^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100411132321 - 2⁶ = 1100411132257 is a prime.

Together with 1100411132323, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100411132293 and 1100411132302.

It is not a weakly prime, because it can be changed into another prime (1100411132323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550205566160 + 550205566161.

It is an arithmetic number, because the mean of its divisors is an integer number (550205566161).

Almost surely, 2^{1100411132321} is an apocalyptic number.

It is an amenable number.

1100411132321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100411132321 is an equidigital number, since it uses as much as digits as its factorization.

1100411132321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1100411132321 its reverse (1232311140011), we get a palindrome (2332722272332).

The spelling of 1100411132321 in words is "one trillion, one hundred billion, four hundred eleven million, one hundred thirty-two thousand, three hundred twenty-one".