Base | Representation |
---|---|
bin | 1010000000100001100101… |
… | …1101001110011111101100 |
3 | 1102221222120222012021212212 |
4 | 2200020121131032133230 |
5 | 2420242431111214200 |
6 | 35223121250345552 |
7 | 2214010452532223 |
oct | 240103135163754 |
9 | 42858528167785 |
10 | 11004133304300 |
11 | 3562910411684 |
12 | 1298811b8b2b8 |
13 | 61a8ba84a246 |
14 | 2a08624a9cba |
15 | 1413994b2035 |
hex | a021974e7ec |
11004133304300 has 18 divisors (see below), whose sum is σ = 23878969270548. Its totient is φ = 4401653321680.
The previous prime is 11004133304299. The next prime is 11004133304321. The reversal of 11004133304300 is 340333140011.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 55020666422 + ... + 55020666621.
Almost surely, 211004133304300 is an apocalyptic number.
11004133304300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11004133304300 is an abundant number, since it is smaller than the sum of its proper divisors (12874835966248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11004133304300 is a wasteful number, since it uses less digits than its factorization.
11004133304300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110041333057 (or 110041333050 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11004133304300 its reverse (340333140011), we get a palindrome (11344466444311).
The spelling of 11004133304300 in words is "eleven trillion, four billion, one hundred thirty-three million, three hundred four thousand, three hundred".
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