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11004135555000 = 233547228615233
BaseRepresentation
bin1010000000100001100110…
…0101110011111110111000
31102221222121010102122021010
42200020121211303332320
52420242432200230000
635223121410513520
72214010510625100
oct240103145637670
942858533378233
1011004135555000
113562911709665
1212988128958a0
1361a8bb157813
142a08628d4200
151413997a8d50
hexa0219973fb8

11004135555000 has 480 divisors, whose sum is σ = 40011099662160. Its totient is φ = 2513871360000.

The previous prime is 11004135554989. The next prime is 11004135555019. The reversal of 11004135555000 is 55553140011.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 2102832384 + ... + 2102837616.

Almost surely, 211004135555000 is an apocalyptic number.

11004135555000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11004135555000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20005549831080).

11004135555000 is an abundant number, since it is smaller than the sum of its proper divisors (29006964107160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11004135555000 is a wasteful number, since it uses less digits than its factorization.

11004135555000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8137 (or 8111 counting only the distinct ones).

The product of its (nonzero) digits is 7500, while the sum is 30.

Adding to 11004135555000 its reverse (55553140011), we get a palindrome (11059688695011).

The spelling of 11004135555000 in words is "eleven trillion, four billion, one hundred thirty-five million, five hundred fifty-five thousand".