Base | Representation |
---|---|
bin | 10100011111110011… |
… | …01111100010101101 |
3 | 1001101220100221222001 |
4 | 22033321233202231 |
5 | 140014034312141 |
6 | 5015534252301 |
7 | 536460161605 |
oct | 121771574255 |
9 | 31356327861 |
10 | 11004213421 |
11 | 4737656463 |
12 | 2171357091 |
13 | 1064a713b6 |
14 | 765689c05 |
15 | 446122a31 |
hex | 28fe6f8ad |
11004213421 has 2 divisors, whose sum is σ = 11004213422. Its totient is φ = 11004213420.
The previous prime is 11004213359. The next prime is 11004213427. The reversal of 11004213421 is 12431240011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5950425321 + 5053788100 = 77139^2 + 71090^2 .
It is an emirp because it is prime and its reverse (12431240011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11004213421 - 215 = 11004180653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11004213427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502106710 + 5502106711.
It is an arithmetic number, because the mean of its divisors is an integer number (5502106711).
Almost surely, 211004213421 is an apocalyptic number.
It is an amenable number.
11004213421 is a deficient number, since it is larger than the sum of its proper divisors (1).
11004213421 is an equidigital number, since it uses as much as digits as its factorization.
11004213421 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11004213421 its reverse (12431240011), we get a palindrome (23435453432).
The spelling of 11004213421 in words is "eleven billion, four million, two hundred thirteen thousand, four hundred twenty-one".
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