Base | Representation |
---|---|
bin | 11001000001010110110001… |
… | …011100000011010001010101 |
3 | 112102122010122211210220200011 |
4 | 121001112301130003101111 |
5 | 103410431244001331402 |
6 | 1030013400311320221 |
7 | 32115304116430405 |
oct | 3101266134032125 |
9 | 472563584726604 |
10 | 110044334011477 |
11 | 320775a37771a8 |
12 | 104133b4980071 |
13 | 49531a0221048 |
14 | 1d26261d6a805 |
15 | cac78b94aed7 |
hex | 6415b1703455 |
110044334011477 has 2 divisors, whose sum is σ = 110044334011478. Its totient is φ = 110044334011476.
The previous prime is 110044334011393. The next prime is 110044334011483. The reversal of 110044334011477 is 774110433440011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92112505320676 + 17931828690801 = 9597526^2 + 4234599^2 .
It is a cyclic number.
It is not a de Polignac number, because 110044334011477 - 231 = 110042186527829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110044334011877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55022167005738 + 55022167005739.
It is an arithmetic number, because the mean of its divisors is an integer number (55022167005739).
Almost surely, 2110044334011477 is an apocalyptic number.
It is an amenable number.
110044334011477 is a deficient number, since it is larger than the sum of its proper divisors (1).
110044334011477 is an equidigital number, since it uses as much as digits as its factorization.
110044334011477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112896, while the sum is 40.
Adding to 110044334011477 its reverse (774110433440011), we get a palindrome (884154767451488).
The spelling of 110044334011477 in words is "one hundred ten trillion, forty-four billion, three hundred thirty-four million, eleven thousand, four hundred seventy-seven".
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