Base | Representation |
---|---|
bin | 110011001111100101… |
… | …0001110010111011111 |
3 | 101112001012000202122011 |
4 | 1212133022032113133 |
5 | 3300332334040111 |
6 | 122315334132051 |
7 | 10644001210141 |
oct | 1463712162737 |
9 | 345035022564 |
10 | 110044440031 |
11 | 42740243609 |
12 | 193b17b1027 |
13 | a4b9789696 |
14 | 547d070c91 |
15 | 2ce0e75021 |
hex | 199f28e5df |
110044440031 has 2 divisors, whose sum is σ = 110044440032. Its totient is φ = 110044440030.
The previous prime is 110044440007. The next prime is 110044440067. The reversal of 110044440031 is 130044440011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110044440031 - 213 = 110044431839 is a prime.
It is a super-2 number, since 2×1100444400312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110044439984 and 110044440011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110044440731) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55022220015 + 55022220016.
It is an arithmetic number, because the mean of its divisors is an integer number (55022220016).
Almost surely, 2110044440031 is an apocalyptic number.
110044440031 is a deficient number, since it is larger than the sum of its proper divisors (1).
110044440031 is an equidigital number, since it uses as much as digits as its factorization.
110044440031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 110044440031 its reverse (130044440011), we get a palindrome (240088880042).
The spelling of 110044440031 in words is "one hundred ten billion, forty-four million, four hundred forty thousand, thirty-one".
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