Base | Representation |
---|---|
bin | 10100011111110101… |
… | …01001010101010101 |
3 | 1001101220210222200011 |
4 | 22033322221111111 |
5 | 140014114401013 |
6 | 5015543320221 |
7 | 536462165665 |
oct | 121772512525 |
9 | 31356728604 |
10 | 11004450133 |
11 | 47377a8296 |
12 | 2171450071 |
13 | 1064b25071 |
14 | 76570c1a5 |
15 | 44616cc3d |
hex | 28fea9555 |
11004450133 has 2 divisors, whose sum is σ = 11004450134. Its totient is φ = 11004450132.
The previous prime is 11004450101. The next prime is 11004450167. The reversal of 11004450133 is 33105440011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7271484529 + 3732965604 = 85273^2 + 61098^2 .
It is a cyclic number.
It is not a de Polignac number, because 11004450133 - 25 = 11004450101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11004450733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502225066 + 5502225067.
It is an arithmetic number, because the mean of its divisors is an integer number (5502225067).
Almost surely, 211004450133 is an apocalyptic number.
It is an amenable number.
11004450133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11004450133 is an equidigital number, since it uses as much as digits as its factorization.
11004450133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 11004450133 its reverse (33105440011), we get a palindrome (44109890144).
The spelling of 11004450133 in words is "eleven billion, four million, four hundred fifty thousand, one hundred thirty-three".
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