1100510000081 has 2 divisors, whose sum is σ = 1100510000082. Its totient is φ = 1100510000080.

The previous prime is 1100510000059. The next prime is 1100510000087. The reversal of 1100510000081 is 1800000150011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1098689697856 + 1820302225 = 1048184^2 + 42665^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100510000081 - 2¹⁴ = 1100509983697 is a prime.

It is a super-2 number, since 2×1100510000081² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100510000087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550255000040 + 550255000041.

It is an arithmetic number, because the mean of its divisors is an integer number (550255000041).

Almost surely, 2^{1100510000081} is an apocalyptic number.

It is an amenable number.

1100510000081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100510000081 is an equidigital number, since it uses as much as digits as its factorization.

1100510000081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40, while the sum is 17.

Adding to 1100510000081 its reverse (1800000150011), we get a palindrome (2900510150092).

The spelling of 1100510000081 in words is "one trillion, one hundred billion, five hundred ten million, eighty-one", and thus it is an aban number.