1100510000059 has 2 divisors, whose sum is σ = 1100510000060. Its totient is φ = 1100510000058.

The previous prime is 1100510000003. The next prime is 1100510000081. The reversal of 1100510000059 is 9500000150011.

It is an a-pointer prime, because the next prime (1100510000081) can be obtained adding 1100510000059 to its sum of digits (22).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100510000059 - 2¹¹ = 1100509998011 is a prime.

It is a super-2 number, since 2×1100510000059² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100509999994 and 1100510000039.

It is not a weakly prime, because it can be changed into another prime (1100510000099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550255000029 + 550255000030.

It is an arithmetic number, because the mean of its divisors is an integer number (550255000030).

Almost surely, 2^{1100510000059} is an apocalyptic number.

1100510000059 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100510000059 is an equidigital number, since it uses as much as digits as its factorization.

1100510000059 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 225, while the sum is 22.

The spelling of 1100510000059 in words is "one trillion, one hundred billion, five hundred ten million, fifty-nine", and thus it is an aban number.