Base | Representation |
---|---|
bin | 10100011111111010… |
… | …10010110000011101 |
3 | 1001101222010020121101 |
4 | 22033331102300131 |
5 | 140014304102333 |
6 | 5020010233101 |
7 | 536501116126 |
oct | 121775226035 |
9 | 31358106541 |
10 | 11005144093 |
11 | 4738131709 |
12 | 2171725791 |
13 | 1065008ba8 |
14 | 76584d04d |
15 | 44625867d |
hex | 28ff52c1d |
11005144093 has 2 divisors, whose sum is σ = 11005144094. Its totient is φ = 11005144092.
The previous prime is 11005144049. The next prime is 11005144133. The reversal of 11005144093 is 39044150011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10330079769 + 675064324 = 101637^2 + 25982^2 .
It is a cyclic number.
It is not a de Polignac number, because 11005144093 - 221 = 11003046941 is a prime.
It is a super-2 number, since 2×110051440932 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11005144193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502572046 + 5502572047.
It is an arithmetic number, because the mean of its divisors is an integer number (5502572047).
Almost surely, 211005144093 is an apocalyptic number.
It is an amenable number.
11005144093 is a deficient number, since it is larger than the sum of its proper divisors (1).
11005144093 is an equidigital number, since it uses as much as digits as its factorization.
11005144093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 28.
The spelling of 11005144093 in words is "eleven billion, five million, one hundred forty-four thousand, ninety-three".
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