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11005153 is a prime number
BaseRepresentation
bin101001111110…
…110011100001
3202201010020021
4221332303201
510304131103
61031513441
7162353665
oct51766341
922633207
1011005153
116237375
123828881
132384233
1416668a5
15e75bbd
hexa7ece1

11005153 has 2 divisors, whose sum is σ = 11005154. Its totient is φ = 11005152.

The previous prime is 11005151. The next prime is 11005157. The reversal of 11005153 is 35150011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7033104 + 3972049 = 2652^2 + 1993^2 .

It is a cyclic number.

It is not a de Polignac number, because 11005153 - 21 = 11005151 is a prime.

It is a super-2 number, since 2×110051532 = 242226785106818, which contains 22 as substring.

Together with 11005151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11005151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502576 + 5502577.

It is an arithmetic number, because the mean of its divisors is an integer number (5502577).

Almost surely, 211005153 is an apocalyptic number.

It is an amenable number.

11005153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11005153 is an equidigital number, since it uses as much as digits as its factorization.

11005153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75, while the sum is 16.

The square root of 11005153 is about 3317.4015433770. The cubic root of 11005153 is about 222.4327314216.

Adding to 11005153 its reverse (35150011), we get a palindrome (46155164).

The spelling of 11005153 in words is "eleven million, five thousand, one hundred fifty-three".