Base | Representation |
---|---|
bin | 110011001111110110… |
… | …0110011100000011111 |
3 | 101112001211002022111210 |
4 | 1212133230303200133 |
5 | 3300342144130210 |
6 | 122320300315503 |
7 | 10644141233604 |
oct | 1463754634037 |
9 | 345054068453 |
10 | 110053505055 |
11 | 4274537526a |
12 | 193b4842b93 |
13 | a4bb6117c0 |
14 | 54803506ab |
15 | 2ce1b65e20 |
hex | 199fb3381f |
110053505055 has 32 divisors (see below), whose sum is σ = 192844753920. Its totient is φ = 53261873280.
The previous prime is 110053504987. The next prime is 110053505083. The reversal of 110053505055 is 550505350011.
It is a de Polignac number, because none of the positive numbers 2k-110053505055 is a prime.
It is a super-2 number, since 2×1100535050552 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4771351 + ... + 4794360.
It is an arithmetic number, because the mean of its divisors is an integer number (6026398560).
Almost surely, 2110053505055 is an apocalyptic number.
110053505055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
110053505055 is a deficient number, since it is larger than the sum of its proper divisors (82791248865).
110053505055 is a wasteful number, since it uses less digits than its factorization.
110053505055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9565791.
The product of its (nonzero) digits is 9375, while the sum is 30.
Adding to 110053505055 its reverse (550505350011), we get a palindrome (660558855066).
The spelling of 110053505055 in words is "one hundred ten billion, fifty-three million, five hundred five thousand, fifty-five".
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