11005555043321 has 2 divisors, whose sum is σ = 11005555043322. Its totient is φ = 11005555043320.

The previous prime is 11005555043309. The next prime is 11005555043323. The reversal of 11005555043321 is 12334055550011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6991899408400 + 4013655634921 = 2644220^2 + 2003411^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11005555043321 is a prime.

It is a super-2 number, since 2×11005555043321² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 11005555043323, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11005555043323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502777521660 + 5502777521661.

It is an arithmetic number, because the mean of its divisors is an integer number (5502777521661).

Almost surely, 2^{11005555043321} is an apocalyptic number.

It is an amenable number.

11005555043321 is a deficient number, since it is larger than the sum of its proper divisors (1).

11005555043321 is an equidigital number, since it uses as much as digits as its factorization.

11005555043321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45000, while the sum is 35.

The spelling of 11005555043321 in words is "eleven trillion, five billion, five hundred fifty-five million, forty-three thousand, three hundred twenty-one".