Base | Representation |
---|---|
bin | 10100100000000000… |
… | …01111010111101101 |
3 | 1001102000120111100201 |
4 | 22100000033113231 |
5 | 140020003313103 |
6 | 5020034553501 |
7 | 536510514364 |
oct | 122000172755 |
9 | 31360514321 |
10 | 11005916653 |
11 | 473860a096 |
12 | 2171a38891 |
13 | 1065219724 |
14 | 7659b07db |
15 | 44635c51d |
hex | 29000f5ed |
11005916653 has 2 divisors, whose sum is σ = 11005916654. Its totient is φ = 11005916652.
The previous prime is 11005916641. The next prime is 11005916707. The reversal of 11005916653 is 35661950011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10539486244 + 466430409 = 102662^2 + 21597^2 .
It is an emirp because it is prime and its reverse (35661950011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11005916653 is a prime.
It is a super-2 number, since 2×110059166532 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11005919653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502958326 + 5502958327.
It is an arithmetic number, because the mean of its divisors is an integer number (5502958327).
Almost surely, 211005916653 is an apocalyptic number.
It is an amenable number.
11005916653 is a deficient number, since it is larger than the sum of its proper divisors (1).
11005916653 is an equidigital number, since it uses as much as digits as its factorization.
11005916653 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24300, while the sum is 37.
The spelling of 11005916653 in words is "eleven billion, five million, nine hundred sixteen thousand, six hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •