Base | Representation |
---|---|
bin | 1010000000101010001110… |
… | …1111010100110010001111 |
3 | 1102222012120122200111210211 |
4 | 2200022203233110302033 |
5 | 2420312204021220323 |
6 | 35224143404143251 |
7 | 2214122113313131 |
oct | 240124357246217 |
9 | 42865518614724 |
10 | 11006453304463 |
11 | 35638a0a53091 |
12 | 129915ab37b27 |
13 | 61ab9a3a58c6 |
14 | 2a0a02663051 |
15 | 141482ed470d |
hex | a02a3bd4c8f |
11006453304463 has 2 divisors, whose sum is σ = 11006453304464. Its totient is φ = 11006453304462.
The previous prime is 11006453304409. The next prime is 11006453304481. The reversal of 11006453304463 is 36440335460011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11006453304463 is a prime.
It is a super-2 number, since 2×110064533044632 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11006453304163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5503226652231 + 5503226652232.
It is an arithmetic number, because the mean of its divisors is an integer number (5503226652232).
Almost surely, 211006453304463 is an apocalyptic number.
11006453304463 is a deficient number, since it is larger than the sum of its proper divisors (1).
11006453304463 is an equidigital number, since it uses as much as digits as its factorization.
11006453304463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 40.
Adding to 11006453304463 its reverse (36440335460011), we get a palindrome (47446788764474).
The spelling of 11006453304463 in words is "eleven trillion, six billion, four hundred fifty-three million, three hundred four thousand, four hundred sixty-three".
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