1100999999893 has 2 divisors, whose sum is σ = 1100999999894. Its totient is φ = 1100999999892.

The previous prime is 1100999999887. The next prime is 1100999999929. The reversal of 1100999999893 is 3989999990011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 596442656209 + 504557343684 = 772297^2 + 710322^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100999999893 - 2³⁷ = 963561046421 is a prime.

It is a super-2 number, since 2×1100999999893² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100999999843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550499999946 + 550499999947.

It is an arithmetic number, because the mean of its divisors is an integer number (550499999947).

Almost surely, 2^{1100999999893} is an apocalyptic number.

It is an amenable number.

1100999999893 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100999999893 is an equidigital number, since it uses as much as digits as its factorization.

1100999999893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 114791256, while the sum is 76.

The spelling of 1100999999893 in words is "one trillion, one hundred billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, eight hundred ninety-three".