Base | Representation |
---|---|
bin | 10000000001011000101… |
… | …110011101001110010011 |
3 | 10220020212121010020201012 |
4 | 100001120232131032103 |
5 | 121014322022413412 |
6 | 2201443103201135 |
7 | 142354545203522 |
oct | 20013056351623 |
9 | 3806777106635 |
10 | 1101000201107 |
11 | 394a27a01984 |
12 | 15946a8a61ab |
13 | 7ca93085b51 |
14 | 3b4082684b9 |
15 | 1d98d6c1c22 |
hex | 10058b9d393 |
1101000201107 has 2 divisors, whose sum is σ = 1101000201108. Its totient is φ = 1101000201106.
The previous prime is 1101000201101. The next prime is 1101000201109. The reversal of 1101000201107 is 7011020001011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1101000201107 - 218 = 1100999938963 is a prime.
Together with 1101000201109, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1101000201091 and 1101000201100.
It is not a weakly prime, because it can be changed into another prime (1101000201101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550500100553 + 550500100554.
It is an arithmetic number, because the mean of its divisors is an integer number (550500100554).
Almost surely, 21101000201107 is an apocalyptic number.
1101000201107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101000201107 is an equidigital number, since it uses as much as digits as its factorization.
1101000201107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 1101000201107 its reverse (7011020001011), we get a palindrome (8112020202118).
The spelling of 1101000201107 in words is "one trillion, one hundred one billion, two hundred one thousand, one hundred seven".
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