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1101002121253 is a prime number
BaseRepresentation
bin10000000001011000110…
…101110010000000100101
310220020212201201210122201
4100001120311302000211
5121014323020340003
62201443212254501
7142354600421566
oct20013065620045
93806781653581
101101002121253
11394a28aa3581
1215946b471431
137ca935a8b28
143b40860816d
151d98d950b1d
hex10058d72025

1101002121253 has 2 divisors, whose sum is σ = 1101002121254. Its totient is φ = 1101002121252.

The previous prime is 1101002121221. The next prime is 1101002121259. The reversal of 1101002121253 is 3521212001011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1014647246209 + 86354875044 = 1007297^2 + 293862^2 .

It is a cyclic number.

It is not a de Polignac number, because 1101002121253 - 25 = 1101002121221 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1101002121253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101002121259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550501060626 + 550501060627.

It is an arithmetic number, because the mean of its divisors is an integer number (550501060627).

Almost surely, 21101002121253 is an apocalyptic number.

It is an amenable number.

1101002121253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101002121253 is an equidigital number, since it uses as much as digits as its factorization.

1101002121253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 1101002121253 its reverse (3521212001011), we get a palindrome (4622214122264).

The spelling of 1101002121253 in words is "one trillion, one hundred one billion, two million, one hundred twenty-one thousand, two hundred fifty-three".