Base | Representation |
---|---|
bin | 11001000010001011100011… |
… | …100110001010111101001111 |
3 | 112102211112221200212112010122 |
4 | 121002023203212022331033 |
5 | 103412343332041200142 |
6 | 1030055412240455155 |
7 | 32122351445303261 |
oct | 3102134346127517 |
9 | 472745850775118 |
10 | 110101010100047 |
11 | 3209963796841a |
12 | 1042239161a4bb |
13 | 4958633146325 |
14 | 1d28cbb1bbb31 |
15 | cadea74761d2 |
hex | 6422e398af4f |
110101010100047 has 2 divisors, whose sum is σ = 110101010100048. Its totient is φ = 110101010100046.
The previous prime is 110101010099953. The next prime is 110101010100083. The reversal of 110101010100047 is 740001010101011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110101010100047 - 216 = 110101010034511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110101010099998 and 110101010100034.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110101010100847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55050505050023 + 55050505050024.
It is an arithmetic number, because the mean of its divisors is an integer number (55050505050024).
Almost surely, 2110101010100047 is an apocalyptic number.
110101010100047 is a deficient number, since it is larger than the sum of its proper divisors (1).
110101010100047 is an equidigital number, since it uses as much as digits as its factorization.
110101010100047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 17.
Adding to 110101010100047 its reverse (740001010101011), we get a palindrome (850102020201058).
The spelling of 110101010100047 in words is "one hundred ten trillion, one hundred one billion, ten million, one hundred thousand, forty-seven".
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