Base | Representation |
---|---|
bin | 11001000010001011100011… |
… | …101001101001011000001011 |
3 | 112102211112221202120210211201 |
4 | 121002023203221221120023 |
5 | 103412343332304323313 |
6 | 1030055412312205031 |
7 | 32122351456116331 |
oct | 3102134351513013 |
9 | 472745852523751 |
10 | 110101011011083 |
11 | 3209963842a944 |
12 | 10422391999777 |
13 | 49586333a4bc1 |
14 | 1d28cbb377b51 |
15 | cadea75a60dd |
hex | 6422e3a6960b |
110101011011083 has 2 divisors, whose sum is σ = 110101011011084. Its totient is φ = 110101011011082.
The previous prime is 110101011011071. The next prime is 110101011011179. The reversal of 110101011011083 is 380110110101011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110101011011083 - 25 = 110101011011051 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 110101011011083.
It is not a weakly prime, because it can be changed into another prime (110101011011053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55050505505541 + 55050505505542.
It is an arithmetic number, because the mean of its divisors is an integer number (55050505505542).
Almost surely, 2110101011011083 is an apocalyptic number.
110101011011083 is a deficient number, since it is larger than the sum of its proper divisors (1).
110101011011083 is an equidigital number, since it uses as much as digits as its factorization.
110101011011083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 19.
Adding to 110101011011083 its reverse (380110110101011), we get a palindrome (490211121112094).
The spelling of 110101011011083 in words is "one hundred ten trillion, one hundred one billion, eleven million, eleven thousand, eighty-three".
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