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11010110100133 is a prime number
BaseRepresentation
bin1010000000110111110110…
…1100111001001010100101
31102222120000111120222102111
42200031331230321022211
52420342201141201013
635225550314041021
72214311535465034
oct240157554711245
942876014528374
1011010110100133
1135653a8133871
1212999bb719171
1361b330b80321
142a0c6c19871b
151415e906473d
hexa037db392a5

11010110100133 has 2 divisors, whose sum is σ = 11010110100134. Its totient is φ = 11010110100132.

The previous prime is 11010110100103. The next prime is 11010110100181. The reversal of 11010110100133 is 33100101101011.

11010110100133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7509611294689 + 3500498805444 = 2740367^2 + 1870962^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11010110100133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11010110100103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505055050066 + 5505055050067.

It is an arithmetic number, because the mean of its divisors is an integer number (5505055050067).

Almost surely, 211010110100133 is an apocalyptic number.

It is an amenable number.

11010110100133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010110100133 is an equidigital number, since it uses as much as digits as its factorization.

11010110100133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 11010110100133 its reverse (33100101101011), we get a palindrome (44110211201144).

The spelling of 11010110100133 in words is "eleven trillion, ten billion, one hundred ten million, one hundred thousand, one hundred thirty-three".