Base | Representation |
---|---|
bin | 10000000001011001011… |
… | …011011101110101110001 |
3 | 10220020220102022200220102 |
4 | 100001121123131311301 |
5 | 121014333033000423 |
6 | 2201444204122145 |
7 | 142355050405124 |
oct | 20013133356561 |
9 | 3806812280812 |
10 | 1101012000113 |
11 | 394a33630723 |
12 | 159472836355 |
13 | 7ca956574cc |
14 | 3b409a5a3bb |
15 | 1d98e752c28 |
hex | 100596ddd71 |
1101012000113 has 2 divisors, whose sum is σ = 1101012000114. Its totient is φ = 1101012000112.
The previous prime is 1101011999963. The next prime is 1101012000157. The reversal of 1101012000113 is 3110002101011.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 842995749904 + 258016250209 = 918148^2 + 507953^2 .
It is a cyclic number.
It is not a de Polignac number, because 1101012000113 - 210 = 1101011999089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1101012000094 and 1101012000103.
It is not a weakly prime, because it can be changed into another prime (1101012000163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550506000056 + 550506000057.
It is an arithmetic number, because the mean of its divisors is an integer number (550506000057).
Almost surely, 21101012000113 is an apocalyptic number.
It is an amenable number.
1101012000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101012000113 is an equidigital number, since it uses as much as digits as its factorization.
1101012000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 1101012000113 its reverse (3110002101011), we get a palindrome (4211014101124).
The spelling of 1101012000113 in words is "one trillion, one hundred one billion, twelve million, one hundred thirteen", and thus it is an aban number.
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