Base | Representation |
---|---|
bin | 1010000000111000001110… |
… | …1110001110010001110011 |
3 | 1102222120021112122220201122 |
4 | 2200032003232032101303 |
5 | 2420342403021041201 |
6 | 35230004323052455 |
7 | 2214314203203314 |
oct | 240160356162163 |
9 | 42876245586648 |
10 | 11010211112051 |
11 | 356544a156598 |
12 | 1299a2951112b |
13 | 61b348a895a8 |
14 | 2a0c7b77060b |
15 | 141602d68e1b |
hex | a0383b8e473 |
11010211112051 has 2 divisors, whose sum is σ = 11010211112052. Its totient is φ = 11010211112050.
The previous prime is 11010211112023. The next prime is 11010211112053. The reversal of 11010211112051 is 15021111201011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11010211112051 is a prime.
Together with 11010211112053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11010211112053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505105556025 + 5505105556026.
It is an arithmetic number, because the mean of its divisors is an integer number (5505105556026).
Almost surely, 211010211112051 is an apocalyptic number.
11010211112051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11010211112051 is an equidigital number, since it uses as much as digits as its factorization.
11010211112051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 17.
Adding to 11010211112051 its reverse (15021111201011), we get a palindrome (26031322313062).
The spelling of 11010211112051 in words is "eleven trillion, ten billion, two hundred eleven million, one hundred twelve thousand, fifty-one".
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