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11010213133 is a prime number
BaseRepresentation
bin10100100000100001…
…01000010100001101
31001102022122210000121
422100100220110031
5140022103310013
65020311024541
7536562160513
oct122020502415
931368583017
1011010213133
11473aa840a7
12217336b151
13106609221a
147663ac4b3
1544690a58d
hex29042850d

11010213133 has 2 divisors, whose sum is σ = 11010213134. Its totient is φ = 11010213132.

The previous prime is 11010213127. The next prime is 11010213211. The reversal of 11010213133 is 33131201011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10568456809 + 441756324 = 102803^2 + 21018^2 .

It is an emirp because it is prime and its reverse (33131201011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11010213133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11010213833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505106566 + 5505106567.

It is an arithmetic number, because the mean of its divisors is an integer number (5505106567).

Almost surely, 211010213133 is an apocalyptic number.

It is an amenable number.

11010213133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010213133 is an equidigital number, since it uses as much as digits as its factorization.

11010213133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11010213133 its reverse (33131201011), we get a palindrome (44141414144).

The spelling of 11010213133 in words is "eleven billion, ten million, two hundred thirteen thousand, one hundred thirty-three".