Base | Representation |
---|---|
bin | 1010000000111000100100… |
… | …1101010011111111100111 |
3 | 1102222120111221211211022202 |
4 | 2200032021031103333213 |
5 | 2420343100101214012 |
6 | 35230021411445115 |
7 | 2214316401405602 |
oct | 240161115237747 |
9 | 42876457754282 |
10 | 11010303148007 |
11 | 35654970a8569 |
12 | 1299a542b679b |
13 | 61b361b72137 |
14 | 2a0c89a8b339 |
15 | 14160ae98cc2 |
hex | a0389353fe7 |
11010303148007 has 2 divisors, whose sum is σ = 11010303148008. Its totient is φ = 11010303148006.
The previous prime is 11010303148001. The next prime is 11010303148051. The reversal of 11010303148007 is 70084130301011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11010303148007 - 220 = 11010302099431 is a prime.
It is a super-2 number, since 2×110103031480072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11010303148001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505151574003 + 5505151574004.
It is an arithmetic number, because the mean of its divisors is an integer number (5505151574004).
Almost surely, 211010303148007 is an apocalyptic number.
11010303148007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11010303148007 is an equidigital number, since it uses as much as digits as its factorization.
11010303148007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 29.
Adding to 11010303148007 its reverse (70084130301011), we get a palindrome (81094433449018).
The spelling of 11010303148007 in words is "eleven trillion, ten billion, three hundred three million, one hundred forty-eight thousand, seven".
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