Base | Representation |
---|---|
bin | 1010000000111000101011… |
… | …0011111111100011101011 |
3 | 1102222120120211111100200021 |
4 | 2200032022303333203223 |
5 | 2420343123444041011 |
6 | 35230024212421311 |
7 | 2214320146244305 |
oct | 240161263774353 |
9 | 42876524440607 |
10 | 11010330065131 |
11 | 3565500312821 |
12 | 1299a61317837 |
13 | 61b367607b27 |
14 | 2a0c8d496975 |
15 | 14160d514471 |
hex | a038acff8eb |
11010330065131 has 2 divisors, whose sum is σ = 11010330065132. Its totient is φ = 11010330065130.
The previous prime is 11010330065099. The next prime is 11010330065227. The reversal of 11010330065131 is 13156003301011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11010330065131 - 25 = 11010330065099 is a prime.
It is a super-2 number, since 2×110103300651312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11010330065096 and 11010330065105.
It is not a weakly prime, because it can be changed into another prime (11010330060131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505165032565 + 5505165032566.
It is an arithmetic number, because the mean of its divisors is an integer number (5505165032566).
Almost surely, 211010330065131 is an apocalyptic number.
11010330065131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11010330065131 is an equidigital number, since it uses as much as digits as its factorization.
11010330065131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 25.
Adding to 11010330065131 its reverse (13156003301011), we get a palindrome (24166333366142).
The spelling of 11010330065131 in words is "eleven trillion, ten billion, three hundred thirty million, sixty-five thousand, one hundred thirty-one".
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