Base | Representation |
---|---|
bin | 1010000000111011001010… |
… | …1111101000010101100011 |
3 | 1102222122022112010002101021 |
4 | 2200032302233220111203 |
5 | 2420401012000310313 |
6 | 35230214503550311 |
7 | 2214342562550503 |
oct | 240166257502543 |
9 | 42878275102337 |
10 | 11011000010083 |
11 | 35658144a4337 |
12 | 129a00975b397 |
13 | 61b443353168 |
14 | 2a0d14449a03 |
15 | 14164c24b78d |
hex | a03b2be8563 |
11011000010083 has 2 divisors, whose sum is σ = 11011000010084. Its totient is φ = 11011000010082.
The previous prime is 11011000010029. The next prime is 11011000010113. The reversal of 11011000010083 is 38001000011011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11011000010083 - 225 = 11010966455651 is a prime.
It is a super-2 number, since 2×110110000100832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11011000010683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505500005041 + 5505500005042.
It is an arithmetic number, because the mean of its divisors is an integer number (5505500005042).
Almost surely, 211011000010083 is an apocalyptic number.
11011000010083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011000010083 is an equidigital number, since it uses as much as digits as its factorization.
11011000010083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 11011000010083 its reverse (38001000011011), we get a palindrome (49012000021094).
The spelling of 11011000010083 in words is "eleven trillion, eleven billion, ten thousand, eighty-three".
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